Golang 如何判断数组某个元素是否存在 (isset)_Golang_

 package main import ( "fmt" "os" ) func main() { if os.Args[1] != "" { fmt.Println("aaa") } else { fmt.Println("bbb") } }

 panic: runtime error: index out of range goroutine 1 [running]: main.main() /root/workspace/go/testn.go:9 +0x100 exit status 2

 package main import ( "fmt" "os" ) func main() { var target string // 用来获取最终需要的os.Args[1] for k, v := range(os.Args) { if k == 1 { // 假设需要获取os.Args[k], k = 1 target = v } } if target != "" { // 不为空则表示os.Arg[1]存在 fmt.Printf("os.Arg[1] = %s", target) } }

 package main import ( "fmt" "regexp" ) func main() { //pattern := "\\d+" //反斜杠要转义 pattern := "[a-zA-Z]" //匹配字母 str := "a1.22.35.4" result, _ := regexp.MatchString(pattern, str) fmt.Println(result) //true }

 package main import "fmt" import "github.com/wxnacy/wgo/arrays" //go get github.com/wxnacy/wgo/arrays 安装包 func main() { str := "342" var numbers []string numbers = append(numbers, "3332", "342", "ssddd", "ssss", "%%%%") index := arrays.ContainsString(numbers, str) if index == -1 { fmt.Printf("not exists") //-1说明不存在 } else { fmt.Println(index) //存在则会返回元素的下标 } }